Question

If a quadratic has a maximum at (4, 2) with roots at (2,

0) and (6, 0), what is a possible equation?

Answer 1

g(x) = - 1/2 * (x^2 - 8x + 12)

Explanation:

Given the information, you have provided.

Zeros: (2,0) and (6,0).

Maximum: (4,2) which is also your (h,k)

f(x) = - (x - 2)*(x - 6)

g(x) = - 1/2 * (x^2 - 8x + 12)

I do not know how to explain this, but -1/2 makes the graph get (4,2) as the maximum.

The red graph is f(x) = - (x - 2)*(x - 6)

The blue graph is your answer g(x) = - 1/2 * (x^2 - 8x + 12)