Question

The population of two cities of 660000 people. If the population of the first city is equal to 32% of the population of the second city, what is the population of the first city?

Answer 1

To find the population of the first city, set up an equation using the information that the first city's population is 32% of the second city's population, with a combined population of 660,000. Solving this equation yields that the first city's population is 160,000.

Step-by-step explanation:

The question involves calculating the population of the first city when it is known to be 32% of the population of the second city, and the combined population of both cities is 660,000 people. To find this, we need to set up an equation and solve for the population of the first city.

Calculation Steps:

Let the population of the first city be F and the population of the second city be S.

Given that F is 32% of S, we write it as F = 0.32S.

We also know that F + S = 660,000.

Substitute 0.32S for F in the second equation, which gives us 0.32S + S = 660,000.

Simplify to get 1.32S = 660,000.

Divide both sides by 1.32 to get S = 500,000.

Substitute S back into the equation F = 0.32S to get F = 0.32 x 500,000.

Therefore, the population of the first city is 160,000.

Answer 2

population of 1st city =660,000

Step-by-step explanation:

Let the population of second city be x

given that

population of the first city is equal to 32% of the population of the second city

Therefore

population of 1st city = 32% of the population of the second city

32% of x = (32/100)*x

total population of two cities = x + (32/100)*x = (100x+32x)/100 = 132x/100

Also, population of two cities = 660000

thus,

132x/100 = 660000

=> 132x = 660000*100 = 66000000

=> x = 66000000/132 = 2,062,500

Thus, population of 2nd city is 2,062,500

population of 1st city = (32/100)*x = 32/100 * 2,062,500 = 660,000