Question

The smallest of 6 consecutive integers is p, and the greatest is q. What is the value of the average of p and q in terms of p?

A. p+2.5
B. 2p+6
———-
2
C. 6p-2.5
D. 4p
——
6+p

Answer 1

Option A.

Explanation:

It is given that the smallest of 6 consecutive integers is p. So, all numbers are

`p,p+1,p+2,p+3,p+4,p+5`

The greatest is q.

`q=p+5`

Now, the value of the average of p and q in terms of p is

`Average=(p+q)/(2)`

`Average=(p+p+5)/(2)`

`Average=(2p+5)/(2)`

`Average=(2p)/(2)+(5)/(2)`

`Average=p+2.5`

Therefore, the correct option is A.