Question

Please help! Correct answer only, please! I've been stuck on this assignment since yesterday, and I don't want to lose any more points.

Trudy has a collection of 11 dice, 4 of which have twelve sides.
If Trudy randomly rolls 4 dice in a specific order, what is the probability that just the first 2 of the chosen dice have twelve sides?

Write your answer as a decimal rounded to four decimal places.

Answer 1

Approximately 0.0364

Idk if this is right... :(

Explanation:

4 dice with 12 sides

7 dice without 121 sides.

There is a
`(4)/(11)` chance that the first dice has 12 sides.

There is a
`(3)/(10)` chance that the second dice has 12 sides.

There is a
`(7)/(9)` chance that the third dice doesn't have 12 sides.

There is a
`(3)/(4)` chance that the fourth dice doesn't have 12 sides.

Multiply them up:

`(4)/(11)*(3)/(10)*(7)/(9)*(3)/(4)=(252)/(3960)=0.0363636363636...`

So approximately 0.0364