Question

A box-shaped metal can has dimensions 5 in. by 19 in. by 4 in. high. All of the air inside the can is removed with a vacuum pump. Assuming normal atmospheric pressure outside the can, find the total force (in lb) on one of the 5-by-19 in. sides. (Enter the magnitude.)

Answer 1

The force is
`F = 1397 lb`

Step-by-step explanation:

From the question we are told that

The length of the box is
`l = 19 \ in`

The width of the box is
`w = 5 \ in`

The height is
`h = 4\ in`

The pressure experience on one of the sides is mathematically represented as

`p = (F)/(A)`

Where A is the area of the box which is mathematically evaluated as

`A = l * w`

substituting values

`A = 5 *19`

`A = 95 \ in^2`

This pressure is equivalent to the atmospheric pressure which has a constant value of
`p = 14.7 pi`

This implies that

`14.7 = (F)/(95)`

=>
`F = 14.7 *95`

=>
`F = 1397 lb`