Question

What are the zeros of the function f(x) = x2 + 5x + 5 written in simplest radical form?

A. x=5-+10*square root* 5/2

B. x=-5-+10*square root*5/2

C. x=-5-+*square root*5/2

D. x=5-+*square root*5/2

Answer 1

Explanation:

The function is as follows :

`f(x) = x^2 + 5x + 5`

We need to find the zeroes of the function in the simplest radical form.The zero of the above function is given by :

`x=(-b\pm √(b^2-4ac) )/(2a)`

Here,

b = 5

a = 1

c = 5

So,

`x=(-5\pm √(5^2-4* 1* 5) )/(2(1))\\\\x=(-5\pm √(25-20) )/(2(1))\\\\x=(-5\pm √(5) )/(2)`

Hence, the correct option is (c).