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A 0.40 ohms resistor is made from a wire of length 5m and resistivity 2*10-6 ohms m what is the cross sectional area of the wire

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Answer:

25×10⁻⁶ m² or 25 mm²

Step-by-step explanation:

R = ρL/A

0.40Ω = (2×10⁻⁶ Ωm) (5 m) / A

A = 25×10⁻⁶ m²

A = 25 mm²

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