Answer:
The answer is 105 W
Step-by-step explanation:
Solution
Given that:
The core temperature is = 37.0°C
The skin temperature is = 34.8°C,
The thickness of the tissues is on the average of = 1.00 cm
The surface area = 1.75 m²
The conductivity of tissue is = 0.20 J (s.m. °C)
Now,
The rate of heat transfer through a means of conduction of materials is represented as follows:
Q/ t = kA (T₂ - T₁)/d
Where
k = the thermal conductivity
A = denoted as the surface area
d = the thickness
(T₂ - T₁) = is the temperature difference of the body
Thus
Q/t = kA (T₂ - T₁)/d
We now substitute the values of 1.75 m² for A, 0.20 J/ (s. m. °C) for k, 37.0°C, for T₁, 34.8°C for T₂, 1.00 cm for d
We have the following inputs:
Q/t = (0.20 J/s. m. °C) (1.75 m²) ( 37.0°C- 34.8°C)/ ( (1 cm) (10^⁻2/1 cm))
Now
Q/t = (0.20 J/s. m. °C) (1.75 m²) (3.00 ° C)/ (0.01 m)
Q/t= 1.05/(0.01)
Q/t= 105 J/s
Therefore, the rate of heat conduction is 105 W