Question

Question 18 of 25

4 Points
A boat of mass 450 kg drifts along a river at a speed of 10 m/s to the north.
What impulse is required to decrease the speed of the boat to 6 m/s to the
north?
O A. 2700 kg•m/s north
O B. 2700 kg-m/s south
O C. 1800 kgm/s south
O D. 1800 kg-m/s north
SUBMIT​

Answer 1

Answer: 1800 kg·m/s south

Step-by-step explanation:

m = 450 kg

s = 10 m/s north

We need to find the impulse required to decrease the speed of the boat to 6 m/s to the north.

The equation for impulse is: I = p₂ - p₁

• p refers to momentum (p = m × v)
• p₂ = momentum of ending velocity
• p₁ = momentum of beginning velocity

Since we are ending at a velocity of 6 m/s, we will calculate p₂

• p₂ = (450) × (6) = 2700

We are beginning at 10 m/s, we will calculate p₁

• p₁ = (450) × (10) = 4500

Now we can use the impulse equation.

I = p₂ - p₁

I = (2700) - (4500) = - 1800

The negative in front of the 1800 refers to an impulse in the opposite direction. Since the boat is travelling north, the opposite direction will be south.

Therefore, the impulse required to decrease the speed of the boat from 10 m/s north to 6 m/s north is 1800 kg·m/s south.

Answer 2

C I just done it so yeah