Question

What is an equation of the line that passes through (0,8) and (4,0)?

Answer 1

y= -2×+8

Explanation:

find m(slope)

y2-y1 over x2-x1

substitute using (0,8) and (4,0)

m=-2

y=mx+b

substitute x and y to find b using either (0,8) or (4,0)

0=-2(4) + b

0= -8 +b

0+8= -8+8 +b

8=b

y= -2x + 8

Answer 2

Answer: y=-2x+8

Explanation:

To find the slope of the line, you would use
`(y_(2)-y_(1) )/(x_(2) -x_(1) )`. With the 2 points we are given , we can plug it into this equation to find the slope.

`(0-8)/(4-0) =(-8)/(4) =-2`

Now we know the slope is -2. To find the y-intercept, we know that the x value is 0. We are given that one of the points is (0,8). That means 8 is our y-intercept.

The final equation we get is y=-2x+8.