Answer: .793g
Step-by-step explanation:
.205(1mol/44.01) x=(1/17.031).205(1/44.01)(17.031)=x.793g=xI had this as a problem on my hw and it was confirmed right
Answer:
1.35 g (1mol CO2 / 44.01 g CO2) /1 L = x (1mol N2 / 28.02 g N2) / 1 L
x = 0.86 g N2
5.2m questions
6.7m answers