Question

2x^2+5x+3/x^2-3x-4 divided by 4x^2+2x-6/x^2-8x+16

Answer 1

Answer:
`(x-4)/(2x-2)`

Explanation:

`(2x^2+5x+3)/(x^2-3x-4)` divided by
`(4x^2+2x-6)/(x^2-8x+16)` is the same thing as multiplying
`(2x^2+5x+3)/(x^2-3x-4)` by
`(x^2-8x+16)/(4x^2+2x-6)`.

The equation we get is:

`(2x^2+5x+3)/(x^2-3x-4)*(x^2-8x+16)/(4x^2+2x-6)`

With this equation, we can factor each equation:

`((x+1)(2x+3))/((x+1)(x-4)) *((x-4)(x-4))/(2(x-1)(2x+3))`

We can cancel out like terms since they would be dividing each other:

`(x-4)/(2x-2)`