Question

How many moles of potassium hydroxide are needed to completely react with 1.73 moles of aluminum sulfate according to the following equation: Al2(SO4)3 + 6 KOH ---> 2 Al(OH)3 + 3 K2SO4

Answer 1

10.4mol

Step-by-step explanation:

just took the test and got it right

Answer 2

10.4mol

Step-by-step explanation:

Step 1: Write the balanced equation

Al₂(SO₄)₃ + 6 KOH ⇒ 2 Al(OH)₃ + 3 K₂SO₄

Step 2: Establish the appropriate molar ratio

According to the balanced equation, the molar ratio of Al₂(SO₄)₃ to KOH is 1:6.

Step 3: Calculate the moles of potassium hydroxide needed to completely react with 1.73 moles of aluminum sulfate

`1.73molAl_2(SO_4)_3 * (6molKOH)/(1molAl_2(SO_4)_3) = 10.4molKOH`