Question

Determine the temperature of 2.49mol of a gas contained in a 1.00L vessel at a pressure of 1.41atm.

A. 345K

B. 159K

C. 18.7K

D. 6.90K

Answer 1

Answer: T=6.90 K

Step-by-step explanation:

For this problem, you would use Ideal Gas Law.

`PV=nRT`

P=pressure

V=volume

n=moles

R=ideal gas constant

T=temperature (in Kelvin)

We can fill in these values with what we are given.

P=1.41 atm

V=1.00 L

n=2.49 mol

R=0.08206 Latm/Kmol

T=?K

Since we are looking for T, we can get T alone.

`T=(PV)/(nR)`

`T=((1.41 atm)(1.00L))/((2.49mol)(0.08206Latm/Kmol))`

`T=6.9006 K`

With significant figures, we get
`T=6.90 K`.