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A marble is selected at random from a jar containing 6 red marbles, 4 yellow marbles,

and 3 green marbles. What is the probability that
a) the marble is red?
b) the marble is not yellow?
c) the marble is either red or green?
d) the marble is neither red nor green?
ft
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User Gabbie
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1 Answer

5 votes

Answer:

see below

Explanation:

6 red marbles, 4 yellow marbles, and 3 green marbles. = 13 marbles

a) P(red) = red / total = 6/13

b) P( not yellow) = not yellow/total = (13-4) / 13 = 9/13

c) P(red or green) = (red+green) /total = (6+3)/total = 9/13

d) P(not red or green) = P( yellow) = yellow/total = 4/13

User Omnaest
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4.9k points