Question

For what values of "x" is the inequality 3(x+2)-x<8 true?

x > 1
x < 1
x < 7
x > 7

Answer 1

x < 1

Explanation:

Expand the brackets: 3 * x = 3x and 3 * 2 = 6

Current inequality: 3x + 6 - x < 8

Collect like x terms: 3x - x = 2x

Current inequality: 2x + 6 < 8

Collect like integer terms: subract 6 from both sides

Current inequality: 2x < 2

Convert 2x to x: divide both sides by 2

Final answer = x < 1

Hope this helps :)

Answer 2

Given ↓

• The inequality 3(x+2)-x<8

To Find ↓

• Which values of x make the inequality true

Calculations ↓

We can't determine right off the bat what values of x make this inequality true, so we should solve it first.

First, use the distributive property and distribute 3 :

3(x+2)-x<8

3x+6-x<8

Now subtract 6 on both sides :

3x-x<8-6

3x-x<2

now , subtract the x's :

2x<2

Divide by 2 on both sides :

x<1

So the values of x less than 1 make this inequality true.

Let's try -1 (-1 is less than 1)

Plug it in ↓

3(-1+2)-(-1)<8

3(1)+1<8

3+1<8

4<8

4 is less than 8.

Therefore, the values of x that make this inequality true are indeed less than 1.

hope helpful ~