Answer:
![V=122.5in^3](https://img.qammunity.org/2021/formulas/mathematics/high-school/o27sed4vlo4wcb84mpcnb75ecev6u8j9j4.png)
Explanation:
The volume of a right circular cone is given by:
![V=(\pi r^2h)/(3)](https://img.qammunity.org/2021/formulas/mathematics/high-school/ekon15l1k450e0httcsk6t3x8um3cn7ixq.png)
where r is the radius of the circle and h is the height of the cone, and
is a constant
.
According to the problem the height is:
![h=8.1 in](https://img.qammunity.org/2021/formulas/mathematics/college/5u1rkkbp4k8wdm94avfzeosmcjgz3aazus.png)
and we don't have the radius but we have the diameter, which is useful to find it. We just divide the diameter by 2 to find the radius:
![r=(d)/(2)=(7.6in)/(3)=3.8in](https://img.qammunity.org/2021/formulas/mathematics/college/1h61ogbb3f639yw751my0jgix5npsz61ux.png)
Now, we can find the volume by substituting all the known values:
![V=(\pi r^2h)/(3)](https://img.qammunity.org/2021/formulas/mathematics/high-school/ekon15l1k450e0httcsk6t3x8um3cn7ixq.png)
![V=((3.1416)(3.8in)^2(8.1in))/(3) \\\\V=((3.1416)(14.44in^2)(8.1in))/(3) \\\\V=(367.454in^3)/(3) \\\\V=122.485](https://img.qammunity.org/2021/formulas/mathematics/college/c6ifmc5rsvgreiam1yd5h6n3hufh2npazm.png)
Rounding the volume to the nearest tenth of cubic inch we get:
![V=122.5in^3](https://img.qammunity.org/2021/formulas/mathematics/high-school/o27sed4vlo4wcb84mpcnb75ecev6u8j9j4.png)