Question

a caj register contains $10 and $50 with a total value of$1080. If there are 28 bills total, then how many if each does the register contain?​

Answer 1

Explanation:

We can solve by means of a system of equations:

let x register $ 10

let y register $ 50

Now, we have:

10 * x + 50 * y = 1080

x + y = 28 => <x = 28 - y

replacing:

10 * (28 - y) + 50 * y = 1080

280 - 10 * y + 50 * y = 1080

40 * y = 1080 - 280

y = 800/40

y = 20

now for x:

x = 28 - 20

x = 8

which means that in total there are 8 register of $ 10 and 20 register of $ 50