141k views
1 vote
If y varies directly as x, and y is 48 when x is 6, which expression can be used to find the value of y when x is 2?

1 Answer

3 votes

y = ( 48 *2 ) / 6

Step-by-step explanation:

If y varies directly as x they are directly proportional, which means they relate to each other in the same way....

2 : y = 6: 48

what is y if x = 2?

The value of y can be found if you write it a two fracrions

2 : y = 6 : 48

2 / y = 6 / 48

cross multiply the fractions gives

6*y = 48 *2

divide left and right of the = sign by 6 gives the answer:

y = ( 48 *2 ) / 6

(if you solve it you get y = 12 but that was not the question).

Other method:

multiply left and right of the = sign by y

2 * y/y = y *6 / 48

6y / 48 = 2 * 1

multiply left and right of the = sign by 48

6y * 48/48 = ( 48 *2 )

6y = ( 48 *2 )

divide left and right of the = sign by 6

6/6* y = ( 48 *2 )/6

y = ( 48 *2 ) / 6

(if you solve it you get y = 12 but that was not the question).

User Sungah
by
9.1k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories