Question

How many grams of sodium

hydroxide (NaOH) are required to
dissolve in 232 g of water to make a
2.88 m solution?
[?]g NaOH
Molar mass of NaOH: 39.998 g/mol

Answer 1

`m_(NaOH)=26.7gNaOH`

Step-by-step explanation:

Hello,

In this case, given the molality of the solution which is 2.88 m (mol/kg) we can compute the moles of sodium hydroxide that are dissolved in the 232 grams of water (0.232 kg) as follows:

`m=(n)/(m_(solvent)) \\\\n=m*m_(solvent)=2.88(molNaOH)/(kg)*0.232kg =0.668molNaOH`

Then, by using the molar mass of sodium hydroxide we compute the grams:

`m_(NaOH)=0.668molNaOH*(39.998gNaOH)/(1molNaOH) \\\\m_(NaOH)=26.7gNaOH`

Regards.