Question

How many moles of gas are contained in a 60.0L cylinder at a pressure of 200.0 atm and a temperature of 25.0? A.(490.48 mol) B.(590.84 mol) C.(340.56 mol) D.(540.67 mol)​

Answer 1

Answer: A. 490.48mol

Step-by-step explanation:

Using the ideal gas equation; PV =nRT

where P = Presssure = 200 atm

V = Volume = 60L

n = Number of moles

R = Gas constant = 0.08206 L.atm/mol/K

T = Temperature = 25 °C + 273 = 298K

Make "n" the subject of the formular;

n = PV / RT

= 200 x 60 / 0.08206 x 298

= 490.73 mol, which is closest to option A. 490.48mol