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Calculate the wavelength of a nitrogen molecule moving at a speed of 523m/s.

User Shmoolki
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Answer:

The de-Broglie wavelength of the nitrogen molecule is 0.0272 nm

Step-by-step explanation:

The mass, m, of the nitrogen molecule, N₂ = 14.0076u = 28.0152 × 1.66 × 10⁻²⁷ kg


v_(rms) of N₂ = 523 m/s

The de-Broglie wavelength is given as follows;


de-Broglie \, wavelength = (h)/(m* v_(rms))

Where:

h = Planck's constant = 6.62607004 × 10⁻³⁴ m²·kg/s

Plugging in the values, we have;


de-Broglie \, wavelength = (6.62607004 * 10^(-34))/(28.0152 * 1.66 * 10^(-27)* 523) = 2.72* 10^(-11) \, m

Hence, the de-Broglie wavelength of the nitrogen molecule = 0.0272 nm.

User Blackwing
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