Question

A carousel has a diameter of 6.0-m and completes one rotation every 1.7s. Find the centripetal acceleration of the traveler in m / s2.

Answer 1

The centripetal acceleration of the traveler is
`40.98\ m/s^2`

Step-by-step explanation:

It is given that, A carousel has a diameter of 6.0-m and completes one rotation every 1.7 s.

We need to find the centripetal acceleration of the traveler. It is given by the formula as follows :

`a=(v^2)/(r)`

r is radius of carousel

`v=(2\pi r)/(T)`

So,

`a=(4\pi ^2r)/(T^2)`

Plugging all the values we get :

`a=(4\pi ^2* 3)/((1.7)^2)\\\\a=40.98\ m/s^2`

So, the centripetal acceleration of the traveler is
`40.98\ m/s^2`.