Question

Two bodies of mass m1 and m2 are let fall freely from heights h1 and h2 respectively. The ratio of time taken by the bodies to fall through these heights is :

Answer 1

√h₁/h₂

Step-by-step explanation:

In free fall, the square of the time taken by the body is directly proportional to the height from which it is dropped.

• t₁² ∝ h₁
• t₂² ∝ h₂

Ratio

• t₁²/t₂² = h₁/h₂
• t₁/t₂ = √h₁/h₂

Answer 2

According to second equation of kinematics for free fall

• h=-1/2gt²

So

`\\ \rm\Rightarrow h\propto t^2`

`\\ \rm\Rightarrow h_1:h_2::t_1^2:t_2^2`

`\\ \rm\Rightarrow t_1:t_2::√(h_1):√(h_2)`