Answer:
![cos(x)=-(√(3) )/(2)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/zft9i9km63023mrhym8ca3jogfkry2be05.png)
![sin(x)=(1)/(2)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/aapks10aou4i26xzgh01eviosok16faoul.png)
![tan(x)=-(1)/(√(3) )](https://img.qammunity.org/2021/formulas/mathematics/middle-school/o4bs7bjeznfujwc86ymy0s9uogl9cbibvj.png)
![csc(x)=2](https://img.qammunity.org/2021/formulas/mathematics/middle-school/pbk4meddzxvuv0vg129f9as531936f7o0b.png)
![sec(x)=-(2)/(√(3))](https://img.qammunity.org/2021/formulas/mathematics/middle-school/41ekgfodgl8eellva85n3zxc106gzbevjn.png)
![cot(x)=-√(3)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/y62p7hbc5dtp9gqj8hr3z83rb6kptf9qgj.png)
Explanation:
(I'll just use x for ease of writing)
We have the trig equation
, and we know that its terminal side is in the 2nd quadrant. By using a unit circle, we can determine that the angle is
which has an ordered pair of
![(-(√(3) )/(2),(1)/(2) )](https://img.qammunity.org/2021/formulas/mathematics/middle-school/q8tgncj0vsepn55h3icr2wxq95f8xp3khz.png)
, so
![sin(x)=(1)/(2)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/aapks10aou4i26xzgh01eviosok16faoul.png)
, so
![tan(x)=((1)/(2) )/(-(√(3) )/(2) )=-(1)/(√(3) )](https://img.qammunity.org/2021/formulas/mathematics/middle-school/3tn6rs0nksxyl96qcx6956m8ofbacpvma2.png)
Now that we have sin, cos, and tan, we can just take the reciprocal of each of these to get our answers for csc, sec, and cot.
, so
![csc(x)=2](https://img.qammunity.org/2021/formulas/mathematics/middle-school/pbk4meddzxvuv0vg129f9as531936f7o0b.png)
, so
![sec(x)=-(2)/(√(3))](https://img.qammunity.org/2021/formulas/mathematics/middle-school/41ekgfodgl8eellva85n3zxc106gzbevjn.png)
, so
![cot(x)=-√(3)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/y62p7hbc5dtp9gqj8hr3z83rb6kptf9qgj.png)