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Calculate the ph of a solution containing 0.001 mol dm-3 Naoh
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Calculate the ph of a solution containing 0.001 mol dm-3 Naoh

User Padam Thapa
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Answer:

pOH = - log [molarity of OH-] = - log [ molarity of NaOH] , assuming full dissociation. Thus, pOH = - log ( 0.001) = - (-3) = 3. Thus, the pH of 0.001 mol/dm3 NaOH solution is 11.

Step-by-step explanation:

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User Kodie Grantham
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