Question

A gun mass of 5 kg fired a bullet of mass 10 g with the velocity of 360 km/h. What

is gun’s velocity of pushing behind?

answer fast please

Answer 1

The recoil velocity of the gun is
`0.72\,\,(km)/(h)` and is pointing in opposite direction to the velocity of the bullet.

Explanation:

Use conservation of linear momentum, which states that the momentum of the bullet (product of the bullet's mass times its speed) should equal in absolute value the momentum of the recoiling gun (its mass times its recoil velocity).

We also write the mass of the bullet in the same units as the mass of the gun (for example kilograms). Mass of the bullet = 0.010 kg

In mathematical terms, we have:

`5\, kg * v= 0.01 \,kg\,* 360\,(km)/(h) \\v=(0.01\,*360)/(5) \,\,(km)/(h)\\v=0.72\,\,(km)/(h)`