Question

Differentiate (2x+1) (x³-1)​

Answer 1

The answer is

`(d)/(dx) = 8 {x}^(3) + 3 {x}^(2) - 2`

Step-by-step explanation:

You have to apply Product Rule,

`(dy)/(dx) = u (dv)/(dx) + v (du)/(dx)`

`let \: u = 2x + 1`

`(du)/(dx) = 2`

`let \: v = {x}^(3) - 1`

`(dv)/(dx) = 3 {x}^(2)`

Finally :

`(d)/(dx) = (2x + 1)(3 {x}^(2) ) + ( {x}^(3) - 1)(2)`

`(d)/(dx) = 6 {x}^(3) + 3 {x}^(2) + 2 {x}^(3) - 2`

`(d)/(dx) = 8{x}^(3) + 3 {x}^(2) - 2`