Answer:
the 2nd option
Explanation:
given a quadratic in standard form : y = ax² + bx + c (a ≠ 0 )
• if a > 0 then minimum turning point
• if a < 0 then maximum turning point
the graph here has a minimum turning point , so
the function has a positive leading coefficient.
the function is symmetrical about the y- axis , so is of even degree
the function has 1 turning point at (0, 2 )
the graph does not cross the x- axis so has 0 x- intercepts