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You make an iron (II) sulfate solution with a molarity of 2.1 M. If the solution is 500 mL total, how many grams of iron (II) sulfate is that?

1 Answer

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Answer:

Step-by-step explanation:

2.1>1000

?>500

(500×2.1)÷1000=1.05moles

Mass= molesx molar mass

1.05×(56+32+(16×4))

1.05×152=159.6g

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