Question

A real estate purveyor purchases a 60{,}00060,00060, comma, 000 square foot \left(\text{ft}^2\right)(ft 2 )(, start text, f, t, end text, squared, )warehouse and decides to turn it into a storage facility. The warehouse's width is exactly \dfrac 2 3 3 2 ​ start fraction, 2, divided by, 3, end fraction of its length. What is the warehouse's width? Round your answer to the nearest foot.

Answer 1

200 feet

Explanation:

Area of the warehouse
`=60,000$ ft^2`

Let the length of the warehouse=l

The warehouse's width is exactly
`\frac23` of its length

Therefore: Width of the warehouse
`=\frac23l`

Area =Length X Width

Therefore:

`\frac23l*l=60000\\$Cross multiply\\2l^2=60000*3\\2l^2=180000\\$Divide both sides by 2\\2l^2 / 2=180000 / 2\\l^2=90000\\l^2=300^2\\$Length, l=300 feet\\Recall: Width =\frac23l\\$Therefore, Width of the warehouse=\frac23*300=200$ feet`