Question

What is the magnitude of impulse of a 2.7 gram ping pong ball initially moving at 15 m/s, if hit by a ping pong paddle and then moves the opposite direction at 14/ms

Answer 1

impulse = 0.0783 kg.m/s

Step-by-step explanation:

The impulse is the product of the force and an interval of time. This can be represented in terms of the mass of the body and the change in the velocity of the body in such a time:

`F\Delta t=m\Delta v`
`=|m(v_f-v_i)|`

m: mass of the body = 2.7gm = 0.0027 kg

vf: final velocity = -14m/s

vi: initial velocity = 15m/s

vf is negative because the direction of the ball is opposite to the initial direction:

`|m(v_f-v_i)|=|(0.0027kg)(-14m/s-15m/s)|=0.0783(kg.m)/(s)`

hence, the impulse of the ping pong ball is 0.0783 kg.m/s