20.0k views
3 votes
1. Calculate the total binding energy of 12

6 C.

Answer in units of MeV.



2. Calculate the average binding energy per nucleon of 24

12Mg.

Answer in units of MeV/nucleon.



3. Calculate the average binding energy per nucleon of 85

37Rb.

Answer in units of MeV/nucleon.



4. Find the binding energy per nucleon of 238

92U.

Answer in units of MeV/nucleon.



5. Calculate the total binding energy of 20

10Ne.

Answer in units of MeV.



6. Calculate the total binding energy of 40

20Ca.

Answer in units of MeV.

User Mrugesh
by
5.0k points

1 Answer

1 vote

Answer:

1. B = 79.12 MeV

2. B = -4.39 MeV/nucleon

3. B = 2.40 MeV/nucleon

4. B = 7.48 MeV/nucleon

5. B = -18.72 MeV

6. B = 225.23 MeV

Step-by-step explanation:

The binding energy can be calculated using the followng equation:


B = (Zm_(p) + Nm_(n) - M)*931 MeV/C^(2)

Where:

Z: is the number of protons


m_(p): is the proton's mass = 1.00730 u

N: is the number of neutrons


m_(n): is the neutron's mass = 1.00869 u

M: is the mass of the nucleus

1. The total binding energy of
^(12)_(6)C is:


B = (Zm_(p) + Nm_(n) - M)*931.49 MeV/u


B = (6*1.00730 + 6*1.00869 - 12.011)*931.49 MeV/u = 79.12 MeV

2. The average binding energy per nucleon of
^(24)_(12)Mg is:


B = ((Zm_(p) + Nm_(n) - M))/(A)*931.49 MeV/u

Where: A = Z + N


B = ((12*1.00730 + 12*1.00869 - 24.305))/((12 + 12))*931.49 MeV/u = -4.39 MeV/nucleon

3. The average binding energy per nucleon of
^(85)_(37)Rb is:


B = ((Zm_(p) + Nm_(n) - M))/(A)*931.49 MeV/u


B = ((37*1.00730 + 48*1.00869 - 85.468))/(85)*931.49 MeV/u = 2.40 MeV/nucleon

4. The binding energy per nucleon of
^(238)_(92)U is:


B = ((92*1.00730 + 146*1.00869 - 238.03))/(238)*931.49 MeV/u = 7.48 MeV/nucleon

5. The total binding energy of
^(20)_(10)Ne is:


B = (Zm_(p) + Nm_(n) - M)*931.49 MeV/u


B = (10*1.00730 + 10*1.00869 - 20.180)*931.49 MeV/u = -18.72 MeV

6. The total binding energy of
^(40)_(20)Ca is:


B = (Zm_(p) + Nm_(n) - M)*931.49 MeV/u


B = (20*1.00730 + 20*1.00869 - 40.078)*931.49 MeV/u = 225.23 MeV

I hope it helps you!

User Gourav Singla
by
4.5k points