Question

Determine the equation of the circle graphed below.

10
8
-10 -8
8
-6
-2
F
4
2
N
T
-6.
2
10

Answer 1

`= > {x}^(2) + {y}^(2) + 6x - 14y + 49 = 0`

Explanation:

From the graph we can see that

Diameter = 6 units

=> Radius = 3 units and centre is at (-3,7)

=> Equation is Circle with centre (-3,7) and radius of 3 units will be

`= > {(x + 3)}^(2) + {(y - 7)}^(2) = {3}^(2)`

`= > ( {x}^(2) + 6x + 9) + ( {y}^(2) - 14y + 49) = 9`

`= > {x}^(2) + {y}^(2) + 6x - 14y + 49 = 0`