Question

22.00 g of CO2 has a volume of 50.00 L and a pressure of 0.8210 atm. What must be the

temperature of the gas?

Answer 1

T = 9.875K

Step-by-step explanation:

The ideal gas Law is PV = nRT.

P = Pressure

V = Volume

n = amount of substance

R = 8.314 J/(K. mol)

T = Temperature in Kelvin

22g CO2

CO2 Molar Mass = 44g/mol

C = 12g/mol

O = 16g/mol

P = 0.8210atm

V = 50L

PV = nRT

0.8210 x 50 = 8.314 x 0.5 x T

41.05 = 4.157T

T = 41.05/4.157

T = 9.875K