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A survey indicates that shoppers spend an average of 22 minutes with a standard deviation of 8 minutes in your store and that these times are normally distributed. Find the probability that a randomly selected shopper will spend less than 20 minutes in the store.

1 Answer

1 vote

Answer: 0.401294

Explanation:

z=x-μ/σ

z=20-22/8

z=-0.25

the probability for this z-score is 0.401294.

User Ankit Sompura
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