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If 200.4g of water is mixed with 101.42g of salt the mass of the final solution would be reported as

User Shadyar
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1 Answer

3 votes

Answer:

301.8 g

Step-by-step explanation:

We prepare a solution with 200.4 g of water (solvent) and 101.42 g of salt (solute). The mass of the solution is equal to the sum of the mass of the solvent and the mass of the solute.

m(solution) = m(solute) + m(solvent)

m(solution) = 200.4 g + 101.42 g

m(solution) = 301.8 g (we round-off to one decimal according to the significant figures rules)

User Yaqoob Bhatti
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