181k views
23 votes
Balancing Chemical equations
20.​

Balancing Chemical equations 20.​-example-1
User Ahmed AEK
by
7.1k points

2 Answers

5 votes

Answer:

Count each type of atom in reactants and products. ...

Place coefficients, as needed, in front of the symbols or formulas to increase the number of atoms or molecules of the substances. ...

Repeat steps 1 and 2 until the equation is balanced

Step-by-step explanation:

Step 1: Coefficients Versus Subscripts. When approaching a chemical equation, it is important that you understand the difference between coefficients and subscripts. ...

Step 2: Sum the Atoms. ...

Step 3: Balance the First Element. ...

Step 4: Repeat for the Other Elements. ...

Step 5: Tips.

User Raki
by
6.8k points
6 votes

Answer:

2C6H6 + 15O2 = 12CO2 + 6H2O

Step-by-step explanation:

This is a combustion reaction meaning a substance (in this case Benzene or C6H6) reacts with oxygen gas (O2) and releases energy in the form of light and heat.

so Benzene (C6H6) and Dioxygen (O2) are reactants meaning they are on the left side of the equation

Carbon Dioxide (CO2) and Water (H2O) are the products meaning they are on the right side of the equation

To balance an equation you need an equal amount of each element/compound/polyatomic on each side of the equation

so 2C6H6 + 15O2 = 12CO2 + 6H2O:

(2•6) = 12 C = (12•C) = 12 C ~ 12C = 12C

(2•6) = 12 H = (2•6) = 12 H ~ 12H = 12H

(15•2) = 30 O2 = [(12•2) • (6•1)] = 30 O2

~ 30 O2 = 30 O2

so the equation is now balanced

feel free to ask if you have any other questions

hope this helps :)

User SanthoshSolomon
by
6.7k points