Answer:

Step-by-step explanation:
Given:
Required:
Find the tension TAC and magnitude R of this downward force.
First calculate


To Find tension in AC and magnitude R, use sine rule.

Substitute values:

Solve for T_A_C:


Solve for R.


R = 10.06 kN
Tension AC = 6.296kN
Magnitude,R = 10.06 kN