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The guy wires AB and AC are attached to the top of the transmission tower. The tension in cable AB is 8.7 kN. Determine the required tension T in cable AC such that the net effect of the two cables is a downward force at point A. Determine the magnitude R of this downward force.

User Rockettc
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1 Answer

4 votes

Answer:


T_A_C = 6.296 kN


R = 10.06 kN

Step-by-step explanation:

Given:


T_A_B = 8.7 kN

Required:

Find the tension TAC and magnitude R of this downward force.

First calculate
\alpha, \beta, \gamma


\alpha = tan^-^1 =(40)/(50) = 38. 36


\beta = tan^-^1 =(50)/(30) = 59.04


\gamma = 180 - 38.36 - 59.04 = 82.6

To Find tension in AC and magnitude R, use sine rule.


(sin a)/(T_A_C) = (sin b)/(T_A_B) = (sin c)/(R)

Substitute values:


(sin 38.36)/(T_A_C) = (sin 59.04)/(8.7) = (82.6)/(R)

Solve for T_A_C:


T_A_C = 8.7 * (sin 38.36)/(sin 59.04) =


T_A_C = 8.7 * 0.724 = 6.296 kN

Solve for R.


R = 8.7 * (sin 82.6)/(sin 59.04) =


R = 8.7 * 1.156

R = 10.06 kN

Tension AC = 6.296kN

Magnitude,R = 10.06 kN

The guy wires AB and AC are attached to the top of the transmission tower. The tension-example-1
User Max Lapshin
by
5.5k points