Answer:

Now we can find the second moment with this formula:

And replacing we got:

The variance would be given by:
![Var(X) =E(X^2) -[E(X)]^2 = 21.4 -[3.8]^2 = 6.96](https://img.qammunity.org/2021/formulas/mathematics/college/xkum3dhepwd1kyuolh5atijneqghh9p94r.png)
And the deviation would be:

Explanation:
For this case we have the following distribution given:
X 1 2 7
P(X) 1/5 2/5 2/5
We need to begin finding the mean with this formula:

And replacing we got:

Now we can find the second moment with this formula:

And replacing we got:

The variance would be given by:
![Var(X) =E(X^2) -[E(X)]^2 = 21.4 -[3.8]^2 = 6.96](https://img.qammunity.org/2021/formulas/mathematics/college/xkum3dhepwd1kyuolh5atijneqghh9p94r.png)
And the deviation would be:
