What is the solution of log(3x+4)^125 = 3? (3x+4) is the base. 125 is the argument. x=1/3 x=1 x=7/3 x=4

asked Aug 14, 2023 185k views

16 votes

What is the solution of log(3x+4)^125 = 3? (3x+4) is the base. 125 is the argument.

x=1/3
x=1
x=7/3
x=4

5.3k points

Please log in or register to add a comment.

9 votes

Answer:

x = 1/3

Explanation:

= > log_((3x + 4))125 = 3

$= > {(3x + 4)}^(3) = 125 \: ( \because \: log_(a)b = x = > {a}^(x) = b)$

$= > 3x + 4 = \sqrt[3]{125} = 5$

= > 3x = 5 - 4 = 1

$\therefore \: \: x = (1)/(3)$

Hope you've understood the solution.

Jozala answered Aug 20, 2023

4.5k points

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

5.2m questions

6.7m answers