Answer:
The 99.5% confidence interval for the proportion of all shrubs of this species that will resprout after fire is (0, 0.5745).
Explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.
In which
z is the zscore that has a pvalue of
.
For this problem, we have that:
![n = 18, \pi = (5)/(18) = 0.2778](https://img.qammunity.org/2021/formulas/mathematics/college/nokqo5z67jnsagla7jh60f2fldde9gehvb.png)
99.5% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
The lower limit of this interval is:
![\pi - z\sqrt{(\pi(1-\pi))/(n)} = 0.2778 - 2.81\sqrt{(0.2778*0.7222)/(18)} = -0.01 = 0](https://img.qammunity.org/2021/formulas/mathematics/college/btpkt05npg7xst4xc2xgf70zp1ndghsgzg.png)
We cannot have a negative proportion, so we use 0.
The upper limit of this interval is:
The 99.5% confidence interval for the proportion of all shrubs of this species that will resprout after fire is (0, 0.5745).