Answer:
a) 0.5367feet
b) 0.5223feet
c) 0.7292feet
Explanation:
Given the rate at which an eucalyptus tree will grow modelled by the equation 0.5+6/(t+4)³ feet per year, where t is the time (in years).
The amount of growth can be gotten by integrating the given rate equation as shown;

a) The number of feet that the tree will grow in the second year can be gotten by taking the limit of the integral from t =1 to t = 2
![\int\limits^2_1 {0.5 + (6)/((t+4)^(3) ) } \, dt = [0.5t-3(t+4)^(-2)]^2_1\\= [0.5(2)-3(2+4)^(-2)] - [0.5(1)-3(1+4)^(-2)]\\= [1-3(6)^(-2)] - [0.5-3(5)^(-2)]\\ = [1-(1)/(12)] - [0.5-(3)/(25) ]\\= (11)/(12)-(1)/(2)+(3)/(25)\\ = 0.9167 - 0.5 + 0.12\\= 0.5367feet](https://img.qammunity.org/2021/formulas/mathematics/college/3r3hnb6mcjbn7kvhn91k222zdym8c164hv.png)
b) The number of feet that the tree will grow in the third year can be gotten by taking the limit of the integral from t =2 to t = 3
![\int\limits^3_2 {0.5 + (6)/((t+4)^(3) ) } \, dt = [0.5t-3(t+4)^(-2)]^3_2\\= [0.5(3)-3(3+4)^(-2)] - [0.5(2)-3(2+4)^(-2)]\\= [1.5-3(7)^(-2)] - [1-3(6)^(-2)]\\ = [1.5-(3)/(49)] - [1-(1)/(12) ]\\ = 1.439 - 0.9167\\= 0.5223feet](https://img.qammunity.org/2021/formulas/mathematics/college/9ou237t7mnnteayjn7cw3m2c80in9yabam.png)
c) The total number of feet grown during the second year can be gotten by substituting the value of limit from t = 0 to t = 2 into the equation as shown
![\int\limits^2_0 {0.5 + (6)/((t+4)^(3) ) } \, dt = [0.5t-3(t+4)^(-2)]^2_0\\= [0.5(2)-3(2+4)^(-2)] - [0.5(0)-3(0+4)^(-2)]\\= [1-3(6)^(-2)] - [0-3(4)^(-2)]\\ = [1-(1)/(12)] - [-(3)/(16) ]\\= (11)/(12)+(3)/(16)\\ = 0.9167 - 0.1875\\= 0.7292feet](https://img.qammunity.org/2021/formulas/mathematics/college/97p5kn8hkd0sbynhcwsvukdldg9fyet85u.png)