Question

PLEASE HELP WILL MARK BRAINLKIEST!!!!!!!!

Answer 1

a) -x(4
`x^(2)` -x +1)

b) 4
`x^(3)` (x-1)

c) -12
`x^(2)` - 3x + 3

Explanation:

Most of it is really just a matter of substituting expressions in. here's how i did it:

f(x) = x-1

g(x) = 4
`x^(2)`

a) (f-g) x
`x`

= (x - 1- 4
`x^(2)`) x
`x`

= x(- 4
`x^(2)`+x-1)

= -x (4
`x^(2)` - x + 1)

*you can take the negative out of the bracket or not, i did though - just makes it neater. They are both right.

b) (fxg) x
`x`

= (4
`x^(2)`(x-1)) x
`x`

= 4
`x^(3)` (x-1)

*just bring the x to the front and times it with the 4
`x^(2)`

c) (f+g) x -3

= (x - 1 + 4
`x^(2)`) x -3

= -3 (4
`x^(2)` + x -1)

= -12
`x^(2)` - 3x + 3

*just bring the -3 to the front and times it with the whole bracket to expand since it said evaluate

Hope that helped : )