Question

The expression sin^-1(4/5) has and infinite number of values. True or false?

Answer 1

False

Explanation:

Answer 2

It is indeed false.

`\sin^(-1)x` is a function that takes values of
`x` between -1 and 1, and takes on values between -π/2 and π/2. Most importantly, it's a function that takes *one* value in its domain and assigns it to exactly *one* value in its range. Hence
`\sin^(-1)x` is one-to-one.

It's true that
`\sin x=\frac45` has infinitely many solutions, but
`\sin x` itself is not one-to-one.