Question

If \\(z_1=3+2i\\) and \\(z_2=4+3i\\) and are complex numbers, find \\(z_1z_2\\)

Answer 1

`z_1z_2=(3+2i)(4+3i)=3\cdot4+2i\cdot4+3\cdot3i+2i\cdot3i`

`z_1z_2=12+8i+9i+6i^2`

`i^2=-1`, so

`z_1z_2=12+8i+9i-6=\boxed{6+17i}`