Question

A man measured his height and found 5.7 feet. However, after he carefully measured his height a second time, he found his real height to be 5 feet.What is the percent error the man made the first time he measured his height?

Answer 1

14%

Explanation:

percent error = (experimental measure - real measure)/(real measure) * 100%

percent error = (5.7 ft - 5 ft)/(5 ft) * 100%

percent error = (0.7 ft)/(5 ft) * 100%

percent error = 0.14 * 100%

percent error = 14%

Answer 2

percentage error = 12.28%

Explanation:

5 x 0.14 = 0.7

5 x 1.14 = 5.7

as increase is not the same as error decrease.

We use the same numbers 12.28% = 0.1228.

5.7 x 0.1228 = 0.69996 = 12.28%

5.7 - 0.69996 = 5.00004 foot. As decrease.

And find it is correct.

His error therefore was 12.28% out.

As we work the first numbers 5.7 and can only x by a number to see 5ft

We take 5.7 x 0.1228 and find 0.69996 when taken from 5.7 ft. is unmistakably 5 foot. (5.00004) ft.