Answer:
a.
![8x^(2) -14x-15](https://img.qammunity.org/2021/formulas/mathematics/high-school/7wfsujk2e29mn4hbplt1atc459ne4qhdra.png)
b.
![(x+3)(x+2)](https://img.qammunity.org/2021/formulas/mathematics/high-school/ll70583gsqi9bulk1oc8g8gdxcsb88vkk4.png)
Explanation:
A. There are 3 methods (that I know of). The easiest method is the lattice multiplication, while the most commonly used is the FOIL method (First+Outer+Middle+Last)
For F, take the first terms of the 2 and multiply
![4x*2x=8x^(2)](https://img.qammunity.org/2021/formulas/mathematics/high-school/mjim3s90infu2mzjsgsddppaqh9a5dphsx.png)
For O, take the outer terms and multiply
![4x*-5=-20x](https://img.qammunity.org/2021/formulas/mathematics/high-school/tfxawnqq00tuhh2dlyjfaa6korh0lc3gyl.png)
For I, take the inner terms and multiply
![3*2x=6x](https://img.qammunity.org/2021/formulas/mathematics/high-school/4hnxq8va2libnp2ki2odgno3uc79o5twof.png)
For L, take the last terms and multiply
![3*-5=-15](https://img.qammunity.org/2021/formulas/mathematics/high-school/8lc7y9r9it11elcmv1f9zy1tspkljr8r9l.png)
After that, add all of them up
![8x^(2) +(-20x)+6x+(-15)=8x^(2)-14x-15](https://img.qammunity.org/2021/formulas/mathematics/high-school/n1uo597s7q41lxl5z5zawx59iiecpq6b3e.png)
B. Since the equation is in the form x^2+bx+c,
![(x+?)(x+?)](https://img.qammunity.org/2021/formulas/mathematics/high-school/jca8pv34qlc6l3egr7d2a810rgu5em7gm8.png)
Now we need to find 2 numbers that will add up to 5 and multiply to 6.
Here are some of the combinations of numbers that multiply to 6
3*2
1*6
-3*-2
-1*-6
3 and 2 add up to 5 so:
![(x+3)(x+2)](https://img.qammunity.org/2021/formulas/mathematics/high-school/ll70583gsqi9bulk1oc8g8gdxcsb88vkk4.png)