Question

Help please is for Algebra

Answer 1

`=(8a+6)/(\left(a-3\right)\left(a+3\right))`

the third option is your answer

Explanation:

`(5)/(a-3)+(3)/(a+3)\\\mathrm{Least\:Common\:Multiplier\:of\:}a-3,\:a+3:\quad \left(a-3\right)\left(a+3\right)\\\mathrm{Adjust\:Fractions\:based\:on\:the\:LCM}\\=(5\left(a+3\right))/(\left(a-3\right)\left(a+3\right))+(3\left(a-3\right))/(\left(a+3\right)\left(a-3\right))\\\mathrm{Since\:the\:denominators\:are\:equal,\:combine\:the\:fractions}:\quad (a)/(c)\pm (b)/(c)=(a\pm \:b)/(c)\\=(5\left(a+3\right)+3\left(a-3\right))/(\left(a-3\right)\left(a+3\right))`

`\mathrm{Expand}\:5\left(a+3\right)+3\left(a-3\right):\quad 8a+6\\=(8a+6)/(\left(a-3\right)\left(a+3\right))`