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Select the correct solution in each column of the table.

Solve the following equation.
18
12 + 6s
Examine the given table, and select the accurate number of each type of solution, as well as any real solutions that exist.
Number of
Real Solutions
Number of
Extraneous
Solutions
Real Solutions
0
0
x = 0
1
1
x= 3
2
x = 0, x= 3
N

User Sanz
by
4.2k points

2 Answers

3 votes

Answer:

Number of Real Solutions = 1

Number of Extraneous Solutions = 1

Real Solutions = (x = 3)

User Nawlrus
by
4.7k points
3 votes

The equation has one real solution (x = 3) and one extraneous solution (x = 0), making the total number of real solutions equal to one.

To solve the given equation "3/x - x / x+6 = 18 / x^2 + 6x", let's find a common denominator, which is x(x+6). Multiplying both sides by this common denominator, we get:

3(x+6) - x^2 = 18

Simplifying further:

3x + 18 - x^2 = 18

Rearranging terms:

x^2 - 3x = 0

Factoring out x:

x(x - 3) = 0

This equation has two potential solutions: x = 0 and x = 3. Now, let's check for extraneous solutions, which may occur if a value makes the original equation undefined.

For x = 0, the original equation becomes undefined due to division by zero in the term 3/x. Therefore, x = 0 is an extraneous solution.

For x = 3, the original equation is defined, and substituting x = 3 back into the original equation validates x = 3 as a valid solution.

Now, looking at the table options:

Number of Real Solutions: 1 (since x = 3 is a valid solution).

Number of Extraneous Solutions: 1 (since x = 0 is an extraneous solution).

Real Solutions: x = 3.

Extraneous Solutions: x = 0.

The question probable may be:

Select the correct solution in each column of the table.

Solve the following equation

3/x - x / x+6 = 18 / x^2 +6x

Examine the given table , and select the accurate number of each type of solution as well as any real solutions that exist.

Number of Number of Real solutions

Real solution Extraneous

Solutions

0 0 x = 0

1 1 x = 3

2 2 x = 0 , x=3

User The Exile
by
3.9k points